[Wiki] How to create a simple logout link in the view?

<div id="mainmenu">
  <?php $this->widget('zii.widgets.CMenu',array(
    'items'=>array(
    array('label'=>'Home', 'url'=>array('post/index')),
    array('label'=>'About', 'url'=>array('site/page', 'view'=>'about')),
    array('label'=>'Contact', 'url'=>array('site/contact')),
    array('label'=>'Login', 
              'url'=>array('site/login'), 
              'visible'=>Yii::app()->user->isGuest),
    array('label'=>'Logout ('.Yii::app()->user->name.')', 
              'url'=>array('site/logout'), 
              'visible'=>!Yii::app()->user->isGuest)
    ),
  )); ?>
</div><!-- mainmenu -->

<a href="<?php echo Yii::app()->createAbsoluteUrl('site/logout'); ?>">Logout</a>

public function actionLogout() {
    Yii::app()->user->logout();
    $this->redirect(Yii::app()->homeUrl);
 }

<?php if (!Yii::app()->user->isGuest){
    <a href="<?php echo Yii::app()->createAbsoluteUrl('site/logout'); ?>">Logout</a>
}?>